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​Detailed calculation method for horizontal structure with cladding

Detailed calculation method for horizontal composition (Gray book 2017 edition p229)

Scope of application

  1. The upper limit of ⊿Qa is 13.72kN/m

  2. Surface material is structural plywood T24​ or t28, use N75 or CN75 nails

  3. The length of the nail should be at least 2.5 times the thickness of the face material, and the thickness of the face material should be at least 12 mm. Structural plywood is JAS class 2, surface veneer is J1 (red pine, larch, Douglas fir, black pine, etc.) or J2 (cypress, cypress). , Beituga, Beihi, etc.)

  4. Nail pitch is 75mm or more, edge distance is 10mm or more and t×0.8 or more

  5. The plywood receiver has a cross section of 90 x 90 or more and is 910Provided at intervals of mm

  6. The plywood support should be completely sunk into the horizontal members.

types of nails
nail pitch
roof slope
Detailed drawing of rigid floor structure_edited.jpg
Hard floor horizontal structure
Face material
​nail
k
kN/cm
δv
cm
δu
cm
⊿Pv
kN
GB
kN/cm2
t
cm
Ixy
cm2/cm2
Zxy
cm/cm2
Cxy
 

structural plywood
24 or 28mm

Iron round nail

N75

4.80

0.21

1.53

0.98

4.80

2.4

1.54

0.038

1.31

1.54

nail pitch
mm
PY = ⊿MY = Zxy･⊿Pv =
0.000
KR = ⊿KR = 1/(1/(Ixy･k)+1/(GB･t)) =
P150 = KR /150 = 
0.000
0.000
Pu = ⊿Mu = Cxy･⊿My =
0.000
μ0 = (δu･GB･t + δv･Ixy･k) / (δv･(GB･t+Ixy･k)) =
Ry0 = ⊿My/⊿KR =
0.000
Ry = PY/KR =
0.000
Ru = Ry+(μ0-1)･Ry0 =
μ = Ru/Ry = 
0.000
0.000
0.000
0.2･((2･μ-1)^1/2)･Pu = 
0.000
⊿Qa = min{Py , P150 , 0.2･((2･μ-1)^1/2)･Pu･0.1372} = 
0.000
​Reduction by slope
​Gradient: θ=
0.000
​⊿Qareduction = ⊿Qa･cosθ =
0.000
​Allowable shear force per unit length
⊿Qa =
0.000
kN/m
​単位長さ辺りの許容せん断力
​（勾配による低減考慮）
⊿Qareduction =
0.000
kN/m
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